For the same rise in temperature of one mole of gas at constant volume , heat required for a non - linear tratomic gas is K times that required for monoatomic gas . The value of K is

70 cal of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from 30^@C to 35^@C . What is the amount of heat required to rise the temperature of same gas through the same range al constant volume? (R = 2cal/mole/K)

The H calories of heat is required to increase temperature of one mole of monoatomic gas from 20^(@)C to 30^(@)C at constant volume. The quantity of heat required to increase the temperature of 2 moles of a diatomic gas from 20^(@)C to 25^(@)C at constant volume is

70 cals of heat is required to raise the temperature of 2 moles of an ideal gas at constant pressure from 30^@C to 35^@C . Calculate the amount of heat required to raise the temperature of same gas through same range at constant volume. (R = 2 cal / mole ^@C )

Find the molar specific heat of mixture at constnat volume. It one mole of a monoatomic gas is mixed with three moles of a diatomic gas.

294 joules of heat are required to rise the temperature of 2 mole of an ideal gas at constant pressure from 30^(@)C to 35^(@)C . The amount of heat required to rise the temperature of the same gas through the same range of temperature at constant volume (R = 8.3 Joules/mole/K) is

310 J of heat is required to rise the temperature of 2 moles of an ideal gas at constant pressure from 25^(@)C to 35^(@)C . The amount of heat required to raise the temperature of the gas through the same range at constant volume, is

294 joules of heat is requied to rise the temperature of 2 mole of an ideal gas at constant pressure from 30^(@)C to 35^(@)C . The amount of heat required to rise the temperature of the same gas through the same range of temperature at constant volume (R=8.3 "Joules/mole"-K) is