If `hata,hatb and hatc` are three unit vectors inclined to each other at an angle `theta`. The maximum value of `theta` is

If a,b and c are three unit vectors equally inclined to each other at angle theta . Then, angle between a and the plane of b and c is

If hat a and hatb are two unit vectors inclined at an angle theta , then sin(theta/2)

If hat a and hatb are two unit vectors inclined at an angle theta , then sin(theta/2)

If hata and hatb are two unit vectors inclined at an angle theta , then the value of |hata-hatb| is -

If hata and hatb are unit vectors inclined at angle theta then (1)/(2)|hata+hatb| is

Let hata, hatb and hatc be three unit vectors such that hata=hatb+(hatb xx hatc) , then the possible value(s) of |hata+hatb+hatc|^(2) can be :

Let hata, hatb and hatc be three unit vectors such that hata=hatb+(hatb xx hatc) , then the possible value(s) of |hata+hatb+hatc|^(2) can be :

If hata and hatb are unit vectors inclined at an angle theta then prove that cos "" theta /2 = 1/2 |hata + hatb|

If hata,hatb and hatc are three unit vectors satisfying hata-sqrt3hatb+hatc=hat0 then find the angle between hata and hatc .