In the above figure mercury columns of `10 cms` each are trapped between gas columns of `10 cm` each . If `P_(atm)=75 cm` of `Hg` then the gas pressure in the topmost column will be

Find out the pressure of 10 cm deep water column.

In given figure, an ideal gas is trapped between a mercury column and the closed end of a uniform vertical tube. The upper end of the tube is open to the atmosphere. Initially the lengths of the mercury column and the trapped air colume are 12 cm and 50cm respectively. when the tube is titted solwly in a vertical plane through an angle of 30^(@) with horizontal then the new length of air colume is (x)/(41)m . Find x . Assuming the temperature to remains constant. (P_(atm) = 76 cm of Hg)

In given figure, an ideal gas is trapped between a mercury column and the closed end of a uniform vertical tube. The upper end of the tube is open to the atmosphere. Initially the lengths of the mercury column and the trapped air colume are 12 cm and 50cm respectively. when the tube is titted solwly in a vertical plane through an angle of 30^(@) with horizontal then the new length of air colume is (x)/(41)m . Find x . Assuming the temperature to remains constant. (P_(atm) = 76 cm of Hg)

The difference in the heights of mercury columns in a closed end manometer connected to a gas container is found to be 15 cm. What is the pressure of the gas in terms of Pa ?