Silver forms ccp lattice and x-ray studies of its crystals show that the edge length of its unit cell is 408.6 pm. Calculate the density of silver. (Atomic mass of Ag = 107.9 u)

Explanation

Since it is, cop the number of atoms per unit cell,
Z = 4
Molar mass of silver, `M=108 g mol^(-1)`
Edge length of the unit cell, `a=408.6` pm.
`=408.6xx10^(-10)cm`.
Density of the unit cell `d=(ZM)/(N_(A)a^(3))=(4xx108 gmol^(-1))/(6.022xx10^(23)mol^(-1)xx(408.6xx10^(-10)cm)^(3))`
`d=10.51 gmol^(-3)`.