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The boiling point of benzene is 353.23 K...

The boiling point of benzene is 353.23 K when 1.80 g of a non-volatile, non-ionising solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of solute.
`" "`[Given `K_(b)` for benzene = 2.53 K kg `mol^(-1)`]

Text Solution

Verified by Experts

(a)`M_2 = (k_b xx W_2 xx 1000)/(Delta T_b xx W_1) Delta T_b = 354.11 - 353.23 = 0.88`
`M_2 = (253 xx 1.8 xx 100)/(0.88 xx 90) = 58 g mol^(-1)` .
(b) (i) It is defined as number of moles of the solute dissolved in one kilogram (1000g) of the solvent
(ii) Two solutions having same osmotic pressure at a given temperature are called isotonic solutions.
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