A transistor connected in common-emitter mode configuration is used as an amplifier.If `R_(L)=5k Omega` and input resistance `R_(i)=2k Omega` and current gain is 50.It's power gain is 1250x then x is equal to

A transistor connected at common emitter mode contains load resistance of 5 k Omega . If the input peak voltage is 5 mV and the current gain is 50, find the voltage gain.

A common emitter amplifier has current gain 70. Its load resistance is 5 k Omega and input resistance is 500 Omega . The voltage gain is

A transistor, connected in common emitter configuration, has input resistance R_(i)=2kOmega and load resistance 6kOmega . If beta=60 and an input signal 10mV is applied, calculate the (i) resistance gain, (ii) voltage gain (iii) the power gain and (iv) the value of the output signal.

A transistor connected in common emitter configuration has input resistance R_("in")=2 K Omega and load resistance of 5 K Omega . If beta=60 and an input signal 12 mV is applied , calculate the resistance gain, voltage gain and power gain.

A common-emitter amplifier, has an input resistance of 500Omega and an output resistance of 40 kOmega . If the current gain is 75, then power gain of the transistor is

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 Omega is connected in the collector circuit and the voltage drop across 0.96 and the input resistance of the circuit is 192 Omega , the voltage gain and the power gain of the amplifier will respectively be :

A common emitter circuit is used as an amplifier, its current gain is 50. if input resistance is 1kOmega and input voltage is 5 volt then output current will be