Home
Class 11
PHYSICS
A particle is executing SHM in straight ...

A particle is executing SHM in straight line starting its motion at `t_(1)=0` with zero initial phase.It crosses a point during the motion at successive intervals at `t_(2)=t` and `t_(3)=2t` with a speed v. If its acceleration amplitude is `(2 pi V)/(Nt)` then N is equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

In the equation of motion of a particle y = 0.5 sin (0.3t + 0.1) , the initial phase of motion is -

A partical is moving in a straight line under constant acceleration 4 m//s^(2) . The motion starts from rest. Sketch v-t and s-t graph for the duration t=0 to t=5 s .

A particle is executing simple harmonic motion with an amplitude A and time period T. The displacement of the particles after 2T period from its initial position is

A particle is moving in a straight line. At time t the distance between the particle from its starting point is given by x=t-6t^(2)+t^(3) . Its acceleration will be zero at

A particle in moving in a straight line such that its velocity is given by v=12t-3t^(2) , where v is in m//s and t is in seconds. If at =0, the particle is at the origin, find the velocity at t=3 s .

A particle is moving in a straight line. Its displacement at time t is given by s(I n m)=4t^(2)+2t , then its velocity and acceleration at time t=(1)/(2) second are

A particle execute SHM and its position varies with time as x = A sin omega t . Its average speed during its motion from mean position to mid-point of mean and extreme position is

A particle is moving in a straight line. At time t, the distance between the particle from its starting point is given by x =t- 9t^(2) + t^(3) . lts acceleration will be zero at