If the tangent to the curve `y=f(x)` is perpendicular to `y` -axis then

The tangent to curve y=f(x) is perpendicular to X-axes if

If tangent tto the curve x=at^(2),y=2at is perpendicular to X-axis, then its pointt of contact is

The equation of the tangent to the curve y=x-(4)/(x^(2)) that is perpendicular to y -axis, is

If tangent to the curve y=f(x) at any point is parallel to y -axis,then at that point (dy)/(dx) equals to

Find the point on the curve y=x^3+x^2+x at which the tangent to the curve is perpendicular to the x+y=1

The equation of the tangent to the curve x^(2)+2y=8 which is the perpendicular to x-2y+1=0 is