x and y are the sides of two square such that `y=x-x^(2)`. The rate of change of area of the second square with respect to that of the first square is

x and y are the sides of two squares such that y=x-x^(2). Find the rate of the change of the area of the second square with respect to the first square.

If x and y are the sides of two squares such that y=x-x^(2) , find the rate of the change of the area of the second square with respect to the first square.

If x and y are the sides of two squares such that y=x-x^(2) .Find the change of the area of second square with respect to the area of the first square.

Given two squares of sides x and y such that y=x+x^(2) what is the rate of change of area of the second square with respect to the area of the first square?

Diagonal of first square is half of the diagonal of the other, then the area of second square with respect to the area of the first square will be

If the perimeter and area of a square change at the same rate, then the side of the square is

The length of the diagonal of a square and that of the side of another square are both 10 cm. What is the ratio of the area of the first square to that of the second ?