Test dimensionally if the `v^2=u^2+2ax` may be correct.

Statement 1: Method of dimensions cannot tell whether an equations is correct. And Statement 2: A dimensionally incorrect equation may be correct.

Statement 1: Method of dimensions cannot tell whether an equations is correct. And Statement 2: A dimensionally incorrect equation may be correct.

Check weather the equation is dimensionally correct v^2 = u^2 + 2as^2 .

Test dimensionally if the formula t= 2 pi sqrt(m/(F/x)) may be corect where t is time period, F is force and x is distance.

Test dimensionally if the formula t= 2 pi sqrt(m/(F/x)) may be corect where t is time period, F is force and x is distance.

Test dimensionally if the formula t= 2 pi sqrt(m/(F/x)) may be corect where t is time period, F is force and x is distance.

Check the correctness of the equation by dimensional analysis. V^2-u^2=2 as Where u = initial velocity of a body V = final velocity of a body a = acceleration of the body s = distance covered

v^2 = u^2+2as , where v and u are velocities, ‘a’ acceleration and ‘s’ displacement.Write the dimensions of the following: v^2 = ? U^2= ? 2as = ?

Find the relation v^2 = u^2 + 2as

Derive - v^2 = v_0^2 +2ax