The displacement of a particle executing simple harmonic motion is given by `y=A_(0)+A sin omegat+B cos omegat`. Then the amplitude of its oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y= A_(0) +A sin omega t+ B cos omega t . Then the amplitude of its oscillation is given by:

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

The instantaneous displacement x of a particle executing simple harmonic motion is given by x=a_1sinomegat+a_2cos(omegat+(pi)/(6)) . The amplitude A of oscillation is given by

The displacement of a particle executing simple harmonic motion is given by y = 4 sin(2t + phi) . The period of oscillation is

A simple harmonic motion is represented by x(t) = sin^2 omegat - 2 cos^(2) omegat . The angular frequency of oscillation is given by

A simple harmonic motion is represented by x(t) = sin^2 omegat - 2 cos^(2) omegat . The angular frequency of oscillation is given by

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be