Prove that `sin theta sin(60^(@)-theta) sin(60^(@)+theta)=1/4 sin3theta`.

Prove that sinthetasin(60^(@)+theta)sin(60^(@)-theta)=1/4sin3theta Hence deduce that sin20^(@)sin40^(@)sin60^(@)sin80^(@)=3//16 (OCT-97,INST.93)

sin (60^(@) + theta) - sin ( 60^(@) - theta ) = sin theta.

If sin theta.sin (60+theta)sin (60-theta)=1//4 then theta =

Prove that 4sin theta sin((pi)/(3)+theta)sin((2 pi)/(3)+theta)=sin3 theta

Prove that 4 sin theta sin(pi/3 + theta) sin (pi/3-theta) = sin 3 theta

sin theta sin (60^(@) - theta) sin (60^(@)+ theta) in [-k,k] rArr k=

Prove that: sin theta cos^(3)theta-cos theta sin^(3)theta=(1)/(4)sin4 theta

Prove that abs(sinthetasin(60^@-theta)sin(60^@+theta)) le1/4 for all values of theta .

Prove that: |sin theta sin(60-theta)sin(60+theta)|<=(1)/(4) for all values of theta

Let f(theta) = sinthetaxx sin(60^@ + theta) sin(60^@ - theta) , then