A potentiometer wire has resistance of per unit length of `0.1Omega//m`. A cell of e.m.f. `1.5V` balances against `300cm` length of the wire. Find the current in the potentiometer wire.

A potentiometer wire has a resistance per unit length of 0.1 Omega//m . A cell of emf 1.5V balance against 300 cm length of the wire. Find the current through potentiometer wire.

The resistance per unit length of a wire is 1Omega//"m" . A Leclanche cell of e.m.f. 1.45 V is balanced against 2.9 m length of potentiometer wire. The current through the wire is

The resistance per unit length of a wire is 1Omega//"m" . A Leclanche cell of e.m.f. 1.45 V is balanced against 2.9 m length of potentiometer wire. The current through the wire is

A resistance of potentiometer wire is 1Omega//m . A Daniel cell of e.m.f. 1.08V balances at 216 cm on potentiometer. The current through wire is

A 10 m long potentiometer wire carries a steady current. A standard cell of emf 1.018 V is balanced against a length of 254.5 cm of the wire. What is the potential gradient across the potentiometer wire ?

The wire of potentiometer has resistance 4 Omega and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance 1 Omega . The current flowing through the potentiometer wire is

The wire of potentiometer has resistance 4 Omega and length 1m. It is connected to a cell of e.m.f. 2V and internal resistance 1 Omega . The current flowing through the potentiometer wire is

Resistance of potentiometer wire is 0.1Omega//cm . A cell of emf 1.5V is balanced at 300cm on this potentiometer wire. Calculate the current and balancing length for another cell of emf 1.4V on the same potentiometer wire.