In `Delta ABC`, if : `a = 6, b = 3, cos (A - B) = 4//5`, then : its area =

If in a triangle ABC , a = 6 , b = 3 and cos (A -B) = 4/5 ,then its area in square units, is

If in a !ABC , a = 6 , b = 3 and cos (A -B) = 4/5 ,then its area in square units, is

In Delta ABC, if a = 6, b=3 and cos (A-B) = (4)/(5) " then " angle C =

In DeltaABC, a=6,b=4 and cos (A-B)=4//5 then its area is

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.

In a triangle ABC, two sides are a = 6, b = 3 and cos(A-B) =(4)/(5) then the area of the triangle is

In Delta ABC , a= 6 ,b=3 and cos (A-B) = 4/5 .Then are of triangle is

In Delta ABC , If a =4 , b=3 and COS(A-B) =3/4, then

In Delta ABC , If a =4 , b=3 and COS(A-B) =3/4, then