Assertion : No diffraction is produced in sound waves near a very small opening.
Reason : For diffraction to take place, the aperture of opening should be of same order as wavelength of waves.

Assertion : Modulation index is the degree to which the carrier wave is modulated . Reason : For the strong and clear reception, the value of modulation index should be very small.

Assertion : Modulation index is the degree to which the carrier wave is modulated . Reason : For the strong and clear reception, the value of modulation index should be very small.

Assertion : Radio waves are diffracted by buildings Reason : Radio waves are high energy waves.

Assertion : Radio waves are diffracted by buildings Reason : Radio waves are high energy waves.

Assertion (A): Diffraction takes place with all types of waves. Reason (R): Diffraction is perceptible when the wavelength of the wave is comparable to the dimension of the diffracting device.

Diffraction of light Diffraction of light is the phenomenon of bending of light round corners of an obstacle or aperture and spreading into the geometrical shadow of the diffracting object. The condition for diffraction of light is the size of the aperture should be comparable to the wavelength of incident light. so in daily life, we find that diffraction of sound is more common than the diffraction of light. width of central maxima is {formula= ((2lambdaD)/d) } Two student are separated by a 5 m partition wall in a room that is 10 m high. if both light and sound waves bend around obstacles, we find that the students are unable to see the each other even though they can converse easily. it is due to

Diffraction of light Diffraction of light is the phenomenon of bending of light round corners of an obstacle or aperture and spreading into the geometraicl shadow of the diffracting object. The condition for diffractio of light is the size of the aperature should be comparable to the wavelength of incident light. so in daily life, we find that diffraction of sound is more common than the diffraction of light. width of central maxima is {formula= ((2lambdaD)/d) } In single slit diffraction experiment, if the width of the slit is doubled, if the intensity of central fringe diffraction band becomes.

Assertion: Standard optical diffraction cannot be used for discrimination between different X-ray wavelengths. Reason: The grating spacing is not of the order of X-ray wavelengths.