A wire 2 m in length suspended vertically stretches by. 10 mm when mass of 10 kg is attached to the lower end. The elastic potential energy gain by the wire is (take g = `10 m//s^(2)`)

A wire 2m in length suspended vertically stretches by 1mm when a mass of 20 kg is attached to the lower end. The elastic potential energy gained by wire is ………… (use g= 10 m//s^2)

A metal wire of length L is suspended vertically from a rigid support. When a bob of mass M is attached to the lower end of wire, the elongation of the wire is l:

A metal wire of length L is suspended vertically from a rigid support. When a bob of mass M is attached to the lower end of wire, the elongation of the wire is l:

A wire suspended vertically from one of its ends is stretched by attaching a weight of 100 N to its lower end. What is the elastic potential energy stored in the wire, if the weight stretches the wire by 1.5 mm ?

A wire suspended vertically from one end- stretched by attaching a weight 200 N to the lower end. The weight stretches the wire by 1 mm. The energy gained by the wire is :

A wire suspended vertically is stretched by a 20 kgf. applied to its free end. The increase in length of the wire is 2 mm. The energy stored in the wire is (g=10ms^(-2)) :

A wire suspended vertically is stretched by a 20 kgf applied to its free end. The increase in length of the wire is 2 mm. The energy stored in the wire is (g=10ms^(-2)) :