The gain of a common emitter amplifier is given by `A_(V)=-g_(m)R_(L)`. Does it mean that if we keep on increasing indefinitely `R_(L)`, the gain of the amplifier will also increase indefinitely? Explain your answer.

The gain of a common- emitter ampIifier is given by A_(v)=-g_(m)R_(L) . Does it mean that if we Keep on increasing R_(L) indefiniteIy,the gain of the ampIifier wiII aIso increase indefiniteIy? ExpIain your answer.

Input signal to a common emitter amplifier having a voltage gain of 1000 is given by v_(1) = (0.004 V) sin(omega t + pi/2) . The corresponding output signal is

Draw a simple circuit of a CE transistor amplifier. Explain its working. Show that the voltage gain, A_(v) , of the amplifier is given by A_(v)= -(beta_(ac) R_(I))/(r_(i)) , where beta_(ac) is the current gain, R_(L) is the load resistance and r_(i ) is the input resistance of the transistor. What is the significance of the negative sign in the expression of the voltage gain ?

Draw a simple circuit of a CE transistor amplifier. Explain its working. Show that the voltage gain, A_V of the amplifier is given by A_v = - ( beta_(ac) R_L )/(r_i) where beta_(Ac) is the current gain, R_L is the load resistance and r_1 is the input resistance of the transistor. What is the significance of the negative sign in the expression for the voltage gain?

For a common emitter amplifier, input resistance (R_i) = 500Omega and load resistance R_L = 5000Omega . If beta = 60, then the voltage gain is

Power gain of transistor amplifier with common base circuit or common emitter circuit is large. Does it mean the power is generated by the transistor? Explain.

In a common base transistor amplifier if the input resistance R_(i) is 200 Omega and load resistance R_(L) is 20K Omega , find voltage gain (alpha=0.95)