Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M ` = 6 xx 10^(24) ` Kg, R = 6400 Km)

Find the magnitude of acceleration due to gravity at height of 10 km from the surface of earth.

Derive an expression for critical velocity of satellite. Calculate the acceleration due to gravity at a height of 300 km from the surface of the earth. M = 6xx10^24kg R = 6400 km.

Calculate the acceleration due to gravity at a height of 1600 km from the surface of the Earth. (Given acceleration due to gravity on the surface of the Earth g_(0) = 9.8 ms^(-2) and radius of earth, R = 6400 km).

Given that the radius of the Earth and acceleration due to gravity on the surface of the Earth as 6400 km and 9.8 ms^(-2) , respectively, find the acceleration due to gravity at a height of 5 km from the surface of the Earth.

The depth from the surface of the earth where acceleration due to gravity is 20% of its value on the surface of the earth is (R = 6400 km)

The height at which the value of acceleration due to gravity becomes 50% of that at the surface of the earth. (radius of the earth = 6400 km ) is