Let `vecAB = 3 hati + hatj - hatk and vecAC = hati -hatj + 3hatk` and a point P on the line segment BC is equidistant from AB and AC, then `vec (AP)` is

In a Delta ABC, " if " vec(AB) = hati - 7hatj + hatk and vec(BC) = 3 hatj + hatj + 2 hatk, " then " | vec(CA)|=

In a Delta ABC, " if " vec(AB) = hati - 7hatj + hatk and vec(BC) = 3 hatj + hatj + 2 hatk, " then " | vec(CA)|=

In a Delta ABC, if vec(AB) = 3 hati + 4 hatk, vec(AC) = 5 hati + 2 hatj + 4hatk , then the length of median through A , is

If vec(AB) = 2 hati- 4 hatj +5 hatk and vec(BC)= hat i-2 hatj-3hatk in parallogram ABCD find a unit vector in direction parallel to the diagonal vec(AC) of the parallelogram.

In DeltaABC,vec(AB)=3hati+4hatk and vec(AC)=5hati-2hatj+4hatk . Length of the median drawn from A is ………………

If veca = 3hati - hatj - 4hatk , vecb = -2hati + 4hatj - 3hatk and vec c = hati + 2hatj - hatk then |3veca - 2vec b + 4vec c | is equal to

Let vec(OA)=hati+3hatj-2hatk and vec(OB)=3hati+hatj-2hatk. Then vector vec(OC) biecting the angle AOB and C being a point on the line AB is