`36-:1/4`

The fourth vertex of the parallelogram whose consecutive vertices are (2,4,-1),(3,6-1),(4,5,1) is

Find the value of A in the following : A36-1A4=742

Find the fourth vertex of the parallelogram whose consecutive vertices are (2,4,-1),(3,6,-1)" and " (4,5,1) .

Equation of a directrix of the ellipse x^2/36+y^2/4=1 is

If 3x - (1)/(2x) = 3 , then find the value of (36x^(4) + 1)/(4x^(2)) .

If 36a^(2) + (1)/(4a^(2)) = 31 , then find the value (s) of 6a - (1)/(2a) .

In the expansion of (2^(1/3) +1/(2(3)^(1/3)))^10 then the ratio of 5th term from beginning and 5th term from end is equal to (A) 6^(1/3):1 (B) 4(36)^(1/3):1 (C) 2(36)^(1/3):1 (D) 4(36)^(1/3):1