5a+7b-2c" from "3a-7b+4c

Subtract: (i) 5a + 7b - 2c from 3a - 7b + 4c (ii) a - 2b - 3c from -2a + 5b - 4c (iii) 5x^(2) - 3xy + y^(2) from 7x^(2) - 2xy - 4y^(2) (iv) 6x^(3) - 7x^(2) + 5x - 3 from 4 - 5x + 6x^(2) - 8x^(3) (v) x^(3) + 2x^(2) y + 6xy^(2) - y^(3) from y^(3) - 3xy^(2) - 4x^(2) (vi) -11 x^(2) y^(2) + 7xy - 6 from 9x^(2) y^(2) - 6xy + 9 (vii) -2a + b + 6d from 5a - 2b - 3c

Take away : 2/3+a c-5/7a b+2/3bc from 3/2a b-7/4a c-5/6b c

Subtract 6a+7b-2c from the sum of 4a+2b+3c and 2a-4b+5c

Subtract: (a b)/7-(35)/3b c+6/5ac from 3/5b c-4/5a c

What must be added to 5a , -3b + 2c " to get " 3a - 4b + 7c ?

Subtract : 3a - 5b + c + 2d from 7a - 3b + c - 2d

Subtract : 5a ^(2) b ^(2) c ^(2) from -7a ^(2) b ^(2) c ^(2)

If a,b and c are non-coplanar vectors, prove that 3a-7b-4c, 3a-2b+c and a+b+2c are coplanar.