Find the direction cosines of the normal to the plane `2x+3y-z=4`.

Find the direction cosines of the normal to YZ plane?

Find the direction cosines of the normal to the plane y=3 .

Find the direction cosines of the normal to the plane 12x + 3y - 4z = 65. Also, find the non-parametric form of vector equation of a plane and the length of the perpendicular to the plane from the origin.

Find the direction cosines of the normal to the plane 3x+4=0 .

Find the direction cosines of the normal to the plane x+2y+2z-4=0

Find the direction cosines of the normal to the plane 4x-3y+5z=25 and the length of the perpendicular from the origin on this plane

Find the direction cosines of the normal to the plane is (3x-6y+2z=7 .

Reduce the equation 2x-3y-6z=14 to the normal form and hence fine the length of perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane.

Reduce the equation 2x-3y-6z=14 to the normal form and hence fine the length of perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane.