" 1."2x+y-35=0;3x+4y-65=0

Solve the following system of equations by using the method of cross-multiplication: 2x+y-35=0,quad 3x+4y-65=0

solve for x and y 2x-3y+7=0 3x+4y-5=0

Solve for x and y - 2x+3y-8=0 3x+4y-5=0

Solve the following system of equations by using the method of cross-multiplication: 2x+y-35=0,\ \ \ \ 3x+4y-65=0

The area of the parallelogram formed by lines 2x-y+3=0, 3x+4y-6=0,2x-y+9=0, 3x+4y+4=0 is (in sq units)

2x+3y=0 3x+4y=5

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with the equations x+2y-3=0 , 3x+4y-7=0 , 2x+3y-4=0 , 4x+5y-6=0 , then

Given the four lines with equations x+2y-3=0, 3x+4y-7=0, 2x+3y-4=0 and 4x+5y-6=0 , then: