`a,b,c` are in G.P. and `a+b+c=xb`, `x` can not be (a) `2` (b) `-2` (c) `3` (d) `4`

If a,b, and c are in G.P then a+b,2b and b+ c are in

If a,b,(c+1) are in G.P.and a=(b-c)^(2) then a,b,c are in

If a,b,c are in G.P., then show that a(b-c)^2=c(a-b)^2

If a,b,c, are in G.P. , a.x.b in A.P. and b,y,c in A.P., then : (a)/(x)+( c )/(y) = (A) 1/2 (B) 1 (C) 2 (D) none of these

The numbers a,b,c are in A.P. and a+b+c=60 . The numbers (a-2) , b , (c+3) are in G.P. Then which of the following is not the possible value of a^(2)+b^(2)+c^(2) ?

If a, b, c are in G.P. and b-c, c-a, a-b are in H.P. then find the value of ((a+b+c)^(2))/(b^(2)) .

If l n(a+c),l n(a-c)a n dl n(a-2b+c) are in A.P., then (a) a ,b ,c are in A.P. (b) a^2,b^2, c^2, are in A.P. (c) a ,b ,c are in G.P. d. (d) a ,b ,c are in H.P.