An elevator car whose floor to ceiling distance is equal to `2.7 m` starts ascending with constant acceleration `1.2 m//s^(2)`, 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question `(g=9.8 m//s^(2)`
The bolt's free falls time

An elevator car whose floor to ceiling distance is equal to 2.7 m starts ascending with constant acceleration 1.2 m//s^(2) , 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question (g=9.8 m//s^(2) The velocity of bolt at instant it loses contact is

An elevator car whose floor to ceiling distance is equal to 2.7 m starts ascendiung with constant acceleration 1.2(m)/(s^(2)) , 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question g = 9.8 m//s^(2) Distance moved by elevator car w.r.t. ground frame during the free fall time of the bolt.

An elevator car whose floor to ceiling distance is equal to 2.7 m starts ascendiung with constant acceleration 1.2(m)/(s^(2)) , 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question g=9.8 m//s^(2) Distance covered by the bolt during the free fall time w.r.t. ground frame.

An elevator car whose floor to ceiling distance is equal to 2.7m starts ascending with constant acceleration 1.2 m//s^2. 2 s after the start, a bolt begins falling from the ceiling of the car. Find (a)the time after which bolt hits the floor of the elevator. (b)the net displacement and distance travelled by the bolt, with respect to earth. (Take g=9.8 m//s^2)

An elevator car whose floor to ceiling distance is equal to 2.7m starts ascending with constant acceleration 1.2 m//s^2. 2 s after the start, a bolt begins falling from the ceiling of the car. Find (a)the time after which bolt hits the floor of the elevator. (b)the net displacement and distance travelled by the bolt, with respect to earth. (Take g=9.8 m//s^2)

An elevator whose floor-to-ceiling destance is 2.50 m starts ascending with a constant acceleration of 1.25 ms^(-2) On second after the start, a bolt begins falling from the elevator. Calculate the free fall time of the bolt

. An elevator, whose floor to the ceiling dis tance is 2.50m, starts ascending with a con stant acceleration of 1.25 ms - 2. One second after the start, a bolt begins falling from the ceiling of elevator. The free fall time of the bolt is [g g=10ms^(-2) ]

A lift starts ascending with an acceleration of 4 ft//s^(2) . At the same time a bolt falls from its cieling 6ft above the floor. Find the time taken by it to reach the floor. g= 32 ft//s^(2)