Home
Class 10
MATHS
O is the centre of a circle ,AB is a cho...

O is the centre of a circle ,AB is a chord .From the figure ,`angleACB` is:

A

`90^(@)`

B

Less than `90^(@)`

C

Greater than `90^(@)`

D

`180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CIRCLES

    OSWAAL PUBLICATION|Exercise VERY SHORT ANSWER TYPE QUESTIONS|11 Videos

  • CIRCLES

    OSWAAL PUBLICATION|Exercise SHORT ANSWER TYPE QUESTIONS|4 Videos

  • ARITHMETIC PROGRESSIONS

    OSWAAL PUBLICATION|Exercise TEXTBOOK CORNER EXERCISE 1.4|5 Videos

  • CO-ORDINATE GEOMETRY

    OSWAAL PUBLICATION|Exercise TEXTBOOK CORNER (EXERCISE 7.4)|7 Videos

Similar Questions

Explore conceptually related problems

In the given figure ‘O’ is the centre of the circle and AB, CD are equal chords. If angleAOB = 70^@ . Find the angles of the Delta OCD

In the given figure, O is the centre of the circle and AD is a tangent to the circle at A. If |__CAD=50^(@) and |__ADC=30^(@) , find |__ABO .

IN the given figure ,O is the centre of the circle.XY is a tangent.If anglePQY=55^(@),angleOPQ is:

AP is the tangent to a circle with centre O as shown in the figure .IF angleP=45^(@) and radius of the circle is 5cm,then OP is equal to :

Which of the following statements are true and which are false? In each case give a valid reason for saying so. q: The centre of a circle bisects each chord of the circle

In the figure, ‘O’ is the centre of the circle and OM, ON are the perpendiculars from the centre to the chords PQ and RS. If OM = ON and PQ = 6cm. Find RS

In the figure, O is the centre of a circle of radius 5 cm. T is the point such that OT=13cm and OT intersects the circle at E. If AB is the tangent to the circle at E, find the length of AB.

In the figure 'O' is the centre of the circle angle AOB = 100^@ find angle ADB

In the figure 'O' is the centre of the circle ,PT is a tangent and if anglePTO=30^(@) , find anglePOT

In the given figure, O is the centre of circle such that diameter AB = 13 cm and AC 12 cm. BC is joined. Find the area of the shaded region. ( pi = 314 )