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Prove that the tangent at any point of a...

Prove that the tangent at any point of a circle is perpendicular to the radius through the point of contact.

Text Solution

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The correct Answer is:
PA=PB (C{CS)
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Prove that the tangent at any point of a circle is perpendicular to the radius through the point of tangent

How can you prove the converse of the above theorem. " If a line in the plane of a circle is perpendicular to the radius at its endpoint on the circle, then the line is tangent of the circle ".

Knowledge Check

  • Choose the correct answer and give justification for each. (i) The angle between a tangent to a circle and the radius at the point of contact is

    A
    `60^(@)`
    B
    `30^(@)`
    C
    `45^(@)`
    D
    `90^(@)`
  • The angle formed by the radius at the point of contact with a tangent is:

    A
    `30^(@)`
    B
    `180^(@)`
    C
    `90^(@)`
    D
    `60^(@)`
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