If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1...

If `(dy)/dx = (xy)/(x^2 + y^2), y(1) = 1` and `y(x) = e` then `x =`

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(dy)/(dx)=(x^2y+y)/(xy^2+x)

(dy)/(dx)=(y^(2)-x)/(xy+y)

If x^(3) dy + xy dx = x^(2) dy + 2y dx , y (2) = e and x gt 1 , then y(4) is equal to .

x^(2)dy+(xy + y^(2))dx = 0, y = 1 when x = 1

x^(2)dy+(xy + y^(2))dx = 0, y = 1 when x = 1

x^(2)dy+(xy + y^(2))dx = 0, y = 1 when x = 1

dy/dx + xy = xy^(2) " when "x=1 , y =4

if ( dy )/(dx) =1 + x +y +xy and y ( -1) =0 , then the value of ( y (0) +3 - e^(1//2))

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