A body cools from `50^@C` to `40^@C` in 5 mintues in surrounding temperature `20^@C`. Find temperature of body in next 5 mintues.

A body cools from 50^(@)C to 40^(@)C in 5 minutes. The surrounding temperature is 20^(@)C . What will be its temperature 5 minutes after reading 40^(@)C ? Use approximate method.

A body cools from 70^(@)C to 50^(@)C in 5 minutes. Temperature of surroundings is 20^(@)C . Its temperature after next 10 minutes is

A body cools from 50^(@)C to 40^(@)C in 5 min. The surroundings temperature is 20^(@)C . In what further times (in minutes) will it cool to 30^(@)C ?

A body cools from 50^(@)C to 40^(@)C in 5 min. The surroundings temperature is 20^(@)C . In what further times (in minutes) will it cool to 30^(@)C ?

A body cools from 70^(@)C to 50^(@)C in 5minutes Temperature of surroundings is 20^(@)C Its temperature after next 10 minutes is .

A body takes 10 min to cool from 60^(@)C " to " 50^(@)C . Temperature of surrounding is 25^(@)C . Find the temperature of body after next 10 min.

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 50^@C " to " 40^@C in 5 min. If the temperature of the surrounding is 20^@C , the temperature of the body after the next 5 min would be

A body cools from 71^(@) C. to 50^(@) C in 5 minutes. Temperature of surroundings is 20^(@) C. Its temperature after next 10 minutes is

In 5 minutes, a body cools from 75^@C to 65^@C at room temperature of 25^@C . The temperature of body at the end of next 5 minutes is _______ ""^@C .