When two vectors of magnitudes P and Q are inclined at an angle `theta`, the magnitudes of their resultant is 2P. When the inclination is changed to `180^(@)-theta`, the magnitudes of the resultant is halved. Find the ratio of `P` and `Q`.

Two forces of magnitudes P and Q are inclined at an angle (theta) . The magnitude of their resultant is 3Q. When the inclination is changed to (180^(@)-theta) , the magnitude of the resultant force becomes Q. Find the ratio of the forces.

Two forces of magnitudes P and Q are inclined at an angle (theta) . The magnitude of their resultant is 3Q. When the inclination is changed to (180^(@)-theta) , the magnitude of the resultant force becomes Q. Find the ratio of the forces.

Two vectors inclined at an angle theta have magnitude 3 N and 5 N and their resultant is of magnitude 4 N . The angle theta is

When two forces of magnitude P and Q are perpendicular to each other, their resultant is of magnitude R. When they are at an angle of 180^(@) to each other, their resultant is of magnitude (R )/(sqrt2) . Find the ratio of P and Q.

When two forces of magnitude P and Q are perpendicular to each other, their resultant is of magnitude R. When they are at an angle of 180^(@) to each other their resultant is of magnitude (R)/(sqrt(2)) . Find the ratio of P and Q.

The sum of the magnitudes of two vectors P and Q is 18 and the magnitude of their resultant is 12. If the resultant is perpendicular to one of the vectors, then the magnitudes of the two vectors are

Two forces of magnitudes P and 2Q are inclined to each other at an angle of 150^@ . If the resultant force is perpendicular to P , show that P=sqrt(3)Q .

Two vectors magnitude 2P and P are inclined to each other at a certain angle theta . If the first vector is doubled . Then the resultant vector is increased three times. Find theta .

The maximum magnitude of the resultant of two vectors, vec(P) and vec(Q) ("where" Pgt Q) is x times the minimum magnitude ot the resultant. When the angle between vec(P) and vec(Q)" ""is" " "theta , the magnitude of the resultant is equal to half the sum of the magnitudes of the two vectors. Prove that, cos theta =(x^2+2)/(2(1-x^2))*