`10^-3` W of `5000A` light is directed on a photoelectric cell. If the current in the cell is `0.16muA`, the percentage of incident photons which produce photoelectrons, is

10^(-3) W of 5000 Å light is directed on a photoelectric cell. If the current in the cell is 0.16 mA, the percentage of incident photons which produce photoelectrons, is

Photons of wavelength lamda emitted by a source of power P incident on a photo cell. If the current produced in the cell is I, then the percentage of incident photons which produce current in the photo cell is. (where, h is Planck's constant and c is the speed of light in vacuum)

A 100 W point source emits monochromatic light of wavelength 6000 A Q. 1.5 mW of 4000A light is directed at a photoelectric cell If 0.10 per cent of the incident photons produce photoelectrons, find current is the cell. [Given h=6.6xx10^(-34)Js , c=3xx10^(8)ms^(-1) and e=1.6xx10^(-19)C ]

1.5 mW of 400 nm light is directed at a photoelectric cell. If 0.1% of the incident photons produce photoelectrons, find the current in the cell.

1.5 mW of 400 nm light is directed at a photoelectric cell. If 0.1% of the incident photons produce photoelectrons, find the current in the cell.

1.5 mW of 400 nm light is directed at a photoelectric cell. If 0.1% of the incident photons produce photoelectrons, find the current in the cell.

In photoelectric experiment set up, the maximum kinetic energy (k_("max")) of emitted photoelectrons was measured for different wavelength (lambda) of light used. The graph of k_("max") vs 1/(lambda) ​ was obtained as shown in first figure. In the same setup, keeping the wavelength of incident light fixed at l, the applied potential difference was varied and the photoelectric current was recorded. The result has been shown in graph in second figure. (a) Find lambda is Å (b) Taking the photo efficiency to be 2% (i.e. percentage of incident photons which produce photoelectrons) find the power of light incident on the emitter plate in the experiment. [Take hc = 12400 eV Å ]

A beam of light of wavelength 400nm and power 1.55 mW is directed at the cathode of a photoelectric cell. If only 10% of the incident photons effectively produce photoelectrons, then find current due to these electrons. (given hc=1240 eV-nm, e=1.6xx10^(-19)C )

A beam of light of wavelength 400nm and power 1.55 mW is directed at the cathode of a photoelectric cell. If only 10% of the incident photons effectively produce photoelectrons, then find current due to these electrons. (given hc=1240 eV-nm, e=1.6xx10^(-19)C )