A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.

A particle of mass 0.2 kg moves with simple harmonic motion of amplitude 2 cm. If th~ total energy of the particle is 4 xx10^(-5) J, then the time period of the motion is

A particle of mass 0.2 kg moves with simple harmonic motion of amplitude 2 cm. If the total energy of the particle is 4 xx10^(-5) J, then the time period of the motion is

If particle is excuting simple harmonic motion with time period T, then the time period of its total mechanical energy is :-

If particle is excuting simple harmonic motion with time period T, then the time period of its total mechanical energy is :-

If particle is excuting simple harmonic motion with time period T, then the time period of its total mechanical energy is :-

A particle of mass m= 5g is executing simple harmonic motion with an amplitude 0.3 m and time period pi//5 second. The maximum value of force acting on the particle is

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is

A particle executing simple harmonic motion with an amplitude 5 cm and a time period 0.2 s. the velocity and acceleration of the particle when the displacement is 5 cm is