Home
Class 12
PHYSICS
The acceleration due to gravity g on the...

The acceleration due to gravity g on the earth is `9.8m//s^(2)`. What would be the value of g for a planet whose size is the same as that of earth and the density is twice that of earth?

Promotional Banner

Similar Questions

Explore conceptually related problems

The acceleration due to gravity g on earth is 9.8 m/s^2 . What would the value of g(in SI units) for a planet whose size is the same as that of earth but the density in twice that of earth?

The acceleration due to gravity on the surface of the earth is 9.8 m*s^(-2) . The size of a planet is the same as that of the earth, but its density is twice the density of the earth. The value of the acceleration due to gravity on that planet is

If the acceleration due to gravity on the surface of the earth is 9.8m//s^(2), what will be the acceleration due to gravity on the surface of a planet whose mass and radius both are two times the corresponding quantities for the earth ?

If the acceleration due to gravity on the surface of the Earth is 9.8m//s^(2) , what will be the aceleration due to gravity on the surface of the planet whose mass and radius both are two times the corresponding quantities for the Earth.

The acceleration due to gravity (g) on the surface of the the earth is 9.8 m/s^2 . At what height 'h' will the value of 'g' be half of that on the surface of the earth?

If the acceleration due to gravity on the surface of the Earth is 9.8m//s^2 ,What will be the acceleration due to ravity on the surface of the planet whose mass and radius both are two times the corresponding quantites for the Earth

If g_(1) and g_(2) denote acceleration due to gravity on the surface of the earth and on a planet whose mass and radius is thrice that of earth, then