`x+7y=10,3x-2y=7`

Solve: 2x-7y=7 , 3x+y=22

Solve the following system of equations by matrix method : 5x+7y+2=0 4x+6y+3=0 5x+2y=3 3x+2y=5 3x+4y-5=0 x-y+3=0 3x+y=19 3x-y=23 3x+7y=4 x+2y=-1 3x+y=7 5x+3y=12

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

If 3x-7y=10 and xy=-1, find the value of 9x^(2)+49y^(2)

The equation of the ellipse with focus (-1,1) directrix x-y+3=0 and eccentricity is a. 7x^2+2x y+7y^2+10 x+10 y+7=0 b. 7x^2+2x y+7y^2+10 x-10 y+7=0 c. 7x^2+2x y+7y^2+10 x-10 y+7=0 d. None of these

If 3x+5y=15 and x-2y=10 , what is the value of 2x+7y ?

If 3x-7y=10\ and x y=-1, find the value of 9x^2+49 y^2

If x = 10a, y = 3b , z = 7c and x : y : z = 10 : 3 : 7 , then (7x + 2y + 5z)/(8a + b + 3c) =

IF (5x-7y+10)/1=(3x+2y+1)/8=(11x+4y-10)/9 then what is x+y equal to