Tangent to the curve `y=x^(2)+6` at a point P(1, 7) touches the circle `x^(2)+y^(2)+16x+12y+c=0` at a point Q. Then the coordinates of Q are

Tangent to the curve y=x^(2)+6 at a point (1,7) touches the circle x^(2)+y^(2)+16x+12y+c=0 at a point Q, then the coordinates of Q are (A)(-6,-11) (B) (-9,-13)(C)(-10,-15)(D)(-6,-7)

Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y^2+16x+12y+c=0 at a point Q , then the coordinates of Q are (A) (-6,-11) (B) (-9,-13) (C) (-10,-15) (D) (-6,-7)

Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y^2+16x+12y+c=0 at a point Q , then the coordinates of Q are (A) (-6,-11) (B) (-9,-13) (C) (-10,-15) (D) (-6,-7)

Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y^2+16x+12y+c=0 at a point Q , then the coordinates of Q are (A) (-6,-11) (B) (-9,-13) (C) (-10,-15) (D) (-6,-7)

Tangent to the curve y=x^2+6 at a point (1,7) touches the circle x^2+y^2+16x+12y+c=0 at a point Q , then the coordinates of Q are (A) (-6,-11) (B) (-9,-13) (C) (-10,-15) (D) (-6,-7)

Tangent to the curve y=x^(2)+6 at the point P(1,7) touches the circle x^(2)+y^(2)+16x+12y+c=0 at a point Q. Show that Q=(-6,-7)

If the tangent to the parabola y= x^(2) + 6 at the point (1, 7) also touches the circle x^(2) + y^(2) + 16x + 12y + c =0 , then the coordinates of the point of contact are-

If tangent to the curve x^(2) = y - 6 at point (1,7) touches the circle x^(2) + y^(2) + 16x + 12y + c = 0 then value of c is ………