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(2x+7)/(5)-(3x+11)/(2)=(2x+8)/(3)-5...

(2x+7)/(5)-(3x+11)/(2)=(2x+8)/(3)-5

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(2x)/(5-3x)=(5+3x)/(8x)

(2x)/(3)-(x)/(5)=(3x-11)/(5)

Add the following (8)/(5)x+(11)/(7)y+(9)/(4)xy,-(3)/(2)x-(5)/(3)y-(9)/(5)xy

((2x + 3) - (5x-7)) / (6x + 11) = (8) / (3)

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

Simplify: (9x -7)(2x - 5) - (3x - 8)(5x -3)

Solve for x - (2x+3)/7-(3x-3)/3= (2x-3)/5-8

x=(2*5)/((2!)3)+(2*5*7)/((3!)3^(2))+(2*5*7*9)/((4!)3^(3))+..... then x^(2)+8x+8=

Solve each of the following equations and also check your result in each case: 6. 5 x+(19. 5 x-32. 5)/2=6. 5 x+13+((13 x-26)/2) (3x-8)(3x+2)-\ (4x-11)\ (2x+1)=(x-3)x+7) [(2x+3)+(x+5)]^2+[(2x+3)-(x+5)]^2=10 x^2+92

Solve each of the following equations and also check your result in each case: 6. 5 x+(19. 5 x-32. 5)/2=6. 5 x+13+((13 x-26)/2) (3x-8)(3x+2)-\ (4x-11)\ (2x+1)=(x-3)x+7) [(2x+3)+(x+5)]^2+[(2x+3)-(x+5)]^2=10 x^2+92