Find the percentage error in specific resistance given by `rho = (pir^2R)/(l)` where r is the radius having value `(0.2+-0.02)`cm, R is the resistance of `(60+-2) ohm` and l is the length of `(150+-0.1)`cm.

If 2x% be the percentage error in specific resistance given by rho=(pir^(2)R)/(l) where r is the radius having value (0.2 om 0.01) cm, R is the resistance of (60 pm 3) ohm and l is the length of (150 pm 1.5) cm. Find x.

Calculate the percentage error in specific resistance , rho = pi r^(2) R // l , where r = radius of wire = 0.26 +- 0.02 cm , l = length of wire = 156.0 +- 0.1 cm , and R = resistance of wire = 64 +- 2 Omega .

Calculate the percentage error in specific resistance , rho = pi r^(2) R // l , where r = radius of wire = 0.26 +- 0.02 cm , l = length of wire = 156.0 +- 0.1 cm , and R = resistance of wire = 64 +- 2 Omega .

A hollow cylinder of specific resistance rho , inner radius R , outer radius 2R and length l is as shown in figure. What is the net resistance between the inner and outer surfaces?

A hollow cylinder of specific resistance rho , inner radius R, outer radius 2R and length l is as shown in figure. What is the net resistance between the inner and outer surface?

The specific resistance rho of a circular wire of radius r , resistance R , and length l is given by rho = pi r^(2) R//l . Given : r = 0.24 +- 0.02 cm , R = 30 +- 1 Omega , and l = 4.80 +- 0.01 cm . The percentage error in rho is nearly

The specific resistance rho of a circular wire of radius r , resistance R , and length l is given by rho = pi r^(2) R//l . Given : r = 0.24 +- 0.02 cm , R = 30 +- 1 Omega , and l = 4.80 +- 0.01 cm . The percentage error in rho is nearly

The resistivity of the material of a wire of length 1 and diameter d and resistance R is given by rho=(piRd^(2))/(4l) . The length of the wire I=100.0 cm is measured using a metre scale with a least count of I mm, the diameter d=0.22 cm is measured using an instrument with a least count of 0.01 cm and resistnce R=5.00 ohm is measured with an accuracy of 0.01 ohm. What is the percentage error? Suggest a method to reduced the percentage error.