The lines `ax+by+c=0, bx+cy+a =0, cx+ay+b =0` are concurrent when-

If a,b,c are the sides of Delta ABC and the lines ax+by+c=0, bx+cy+a=0, cx+ay+b=0 are concurrent, then Delta ABC is

If the straight lines ax+by+c=0, bx+cy+a=0 and cx+ay+b=0 are concurrent, then prove that a^(3)+b^(3)+c^(3)=3abc

Prove that the lines ax+by + c = 0, bx+ cy + a = 0 and cx+ay+b=0 are concurrent if a+b+c = 0 or a+b omega + c omega^(2) + c omega = 0 where omega is a complex cube root of unity .

If the straight lines ax + by + c= 0 , bx +cy + a = 0 and cx +ay + b =0 are concurrent , then prove that a^(3)+b^(3)+c^(3)=3abc .

If the lines ax+by+c=0,bx+cy+a=0 and cx+ay+b=0a!=b!=c are concurrent then the point of concurrency is