[" If a function "g(x)" is defined in "[-1,1]" and two vertices of an equilateral "],[" triangle are "(0,0)" and "(x,g(x))" and its area is "(sqrt(3))/(4)," then "g(x)" equals :- "]

Let g(x) be a function defined on [-1,1]. If the area of the equilateral triangle with two of its vertices at (0,0) and (x,g(x)) is (sqrt(3))/(4) , then the function g(x) , is

Let g(x) be a function defined on [-1,1] .If the area of the equilateral triangle with two of its vertices at (0,0) and (x,g(x)) is (sqrt(3))/(4) .then the function g(x) is:

Let g(x) be a function defined on [-1,1]. If the area of the equilateral triangle with two of its vertices at (0,0) and (x,g(x)) is sqrt(3)/4 .then the function g(x) is:

Let g(x) be a function defined on [-1,1]dot If the area of the equilateral triangle with two of its vertices at (0,0) a n d (x ,g(x)) is (a) (sqrt(3))/4 , then the function g(x) is (b) g(x)=+-sqrt(1-x^2) (c) g(x)=sqrt(1-x^2) (d) g(x)=-sqrt(1-x^2) g(x)=sqrt(1+x^2)

Let g(x) be a function defined on [-1,1]dot If the area of the equilateral triangle with two of its vertices at (0,0) a n d (x ,g(x)) is (a) (sqrt(3))/4 , then the function g(x) is (b) g(x)=+-sqrt(1-x^2) (c) g(x)=sqrt(1-x^2) (d) g(x)=-sqrt(1-x^2) g(x)=sqrt(1+x^2)

Let g(x) be a function defined on [-1,1] .If the area of the equilateral triangle with two of its vertices at (0,0) a n d(x,g(x)) is (a) (sqrt(3))/(4) then the function g(x) is (b) g(x)=+-sqrt(1-x^(2))(cx)=sqrt(1-x^(2))(d)g(x)=-sqrt(1-x^(2))g(x)=sqrt(1+x^(2))(d)

Let g(x) be a function defined on [-1, 1]. If the area of the equilateral triangle with two of its vertices at (0, 0) and (x, g(x)) is sqrt(3)//4 , then the function g(x) is

Let g(x) be a function defined on [-1,1]dot If the area of the equilateral triangle with two of its vertices at (0,0) a n d (x ,g(x)) is (sqrt(3))/4 , then the function g(x) is (b) g(x)=+-sqrt(1-x^2) (c) g(x)=sqrt(1-x^2) (d) g(x)=-sqrt(1-x^2) (a) g(x)=sqrt(1+x^2)

Let g(x) be a function defined on [-1,1]dot If the area of the equilateral triangle with two of its vertices at (0,0)a n d(x ,g(x)) is (sqrt(3))/4 , then the function g(x) is g(x)=+-sqrt(1-x^2) g(x)=sqrt(1-x^2) g(x)=-sqrt(1-x^2) g(x)=sqrt(1+x^2)