4_(0)(ax+b)^(2)

A rod of fixed length k slides along the coordinates axes,If it meets the axes at A(a,0) and B(0,b), then the minimum value of (a+(1)/(a))^(2)+(b+(1)/(b))^(2)(a)0(b)8 (c) k^(2)+4+(4)/(k^(2))(d)k^(2)+4+(4)/(k^(2))

If roots of ax^(2)+bx+c=0 are alpha,beta and roots of Ax^(2)+Bx+C=0 are alpha+k,beta+k .then prove that ((B^(2)-4AC))/((b^(2)-4ac))=(A/a)^(2)

If a gt 0 and b^(2) - 4 ac = 0 then solve ax^(3) + (a + b) x^(2) + (b + c) x + c gt 0 .

If a gt 0 and b^(2) - 4 ac = 0 then solve ax^(3) + (a + b) x^(2) + (b + c) x + c gt 0 .

If a gt 0 and b^(2) - 4 ac = 0 then solve ax^(3) + (a + b) x^(2) + (b + c) x + c gt 0 .

Solve the following quadratic equation for x.x^(2)-4ax-b^(2)+4a^(2)=0

If x_(1),x_(2) are the roots of the quadratic equation ax^(2)+bx+c=0 and c ne 0, find the value of (ax_(1)+b)^(-2)+(ax_(2)+b)^(-2) in terms of a,b,c

x^(2)-2ax-(4b^(2)-a^(2))=0

If the equation ax^(2) + by^(2) + (a + b - 4) xy - ax - by - 20 = 0 represents a circle , then its radius is

Find the area bounded between the curves y^(2)=4ax o* x^(2)=4by(a>0,b>0)