Quantity of heat lost in condensation of `10 gm` of steam at `100^@ C` is

Quantity of heat lost in condensation of 10gm of steam at 100C is 2.26x10^k J, then value of k is

If there is no heat loss, the heat released by the condensation of x gram of steam at 100^@C into water at 100^@C can be used to convert y gram of ice at 0^@C into water at 100^@C . Then the ratio of y:x is nearly [Given L_l = 80 cal//gm and L_v= 540 cal//gm ]

If there is no heat loss, the heat released by the condensation of x gram of steam at 100^@C into water at 100^@C can be used to convert y gram of ice at 0^@C into water at 100^@C . Then the ratio of y:x is nearly [Given L_l = 80 cal//gm and L_v= 540 cal//gm ]

Calculate the amount of heat required to convert 10 gm of ice at 0^@C to steam at 100^@C .

Find the quantity of heat required to convert 2gm of ice at -10C into steam at "100C

50 gm of copper is heated to increase its temperature by 10^(@)C. If the same quantity of heat is given to 10 gm of water, the rise in its temperature is (Specific heat of copper =420 Joule-kg^(-1)@C^(-1)