The height of a right circular cone is trisected by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

The height of a right circular cone is trisected by two planes drawn parallel to its base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

The portion of a right circular cone intersected between two parallel planes is ……….

A right circular cone is cut by two planes parallel to the base and trisecting the height. Compare the volumes of three parts into which the cone is divided.

A right circular cone is divided by a plane parallel to its base in two equal volumes. In what ratio will the plane divide the axis of the cone?

A right circular cone is divided by a plane parallel to its base in two equal volumes. In what ratio will the plane divide the axis of the cone?

Two parallel planes which are parallel to the base of a right circular, cone cut the height of the cone are equally. Show that the ratio of the volume of three parts of the cone is 1:17:19.

The height of a right circular cone is 20 cm. A small cone is cut off at the top by a plane parallel to the base. If its volume be 1/8 of the volume of the given cone, at what height above the base is the section made?

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base . The ratio of the volume of the smaller cone to the whole cone is