In a hydraulic jack as shown, mass of the car is m = 800 kg,`A_(1) = 10 cm^(2) , A_(2) = 10 m^(2)` . The minimum force F required to lift the car is

In a hydraulic jack as shown, mass of the car =W=800kg, A_(1)=10cm6(2), A_(2)=10m^(2) . What is the the minimum force F required to lift the car ? Take g=10m//s^(2)

The figure shows a schematic layout of hydraulic jack. The load to be raised weighs 20,000N. The area of cross section of the two pistons are A_(1)=50cm^(2) and A_(2)=10cm^(2) . The force (F) is applied at theend of a ligh lever bar as shown in the figure. Lenghts a and b are 4cm and 36cm respectively. Find the force (F) required to raise the load slowly.

A hydraulic system is used to lift a 2000 kg vehicle in an auto garage. If the vehicle sits on a piston of area 0.5 m^(2) , m, and a force is applied to a piston of area 0.03m^(2) , what is the minimum force that must be applied to lift the vehicle? Given: Area covered by the vehicle on the piston A_(1) = 0.5 m^(2) Weight of the vehicle , F_(1) = 2000 kg xx 9.8 m s^(-2) Area on which force F_(2) is aplied , A_(2) = 0.03 m^(2)

In a hydraulic press, radii of connecting pipes, r_(1) and r_(2) are in the ratio 1:2 . In order to lift a heavy mass M on the larger piston, the small piston must be pressed through a minimum force f equal to

In a hydraulic press, radii of connecting pipes, r_(1) and r_(2) are in the ratio 1:2 . In order to lift a heavy mass M on the larger piston, the small piston must be pressed through a minimum force f equal to

An automobile back is lifted by a hydraulic jack that consists of two pistons. The large piston is 70 cm in diameter and the small piston is 8 cm in dimater. If W is the weight of the car, how much smaller a force is required on the small piston in order to lift the car ?

In a hydraulic lift the radius of small piston is 5.0 cm and that of larger piston is 15cm . Calculate the force F, if the mass of the car to be lifted is 1350 kg ( g=9.8 ms^-2 )