`cot(A+B)=(cotA.cotB-1)/(cotB+cotA)`

Prove that- cot(A+B)=(cotA.cotB-1)/(cotA+cotB)

If tan(A+B)=(tanA+tanB)/(1-tanAtanB) , then by applying the result tantheta=(1/cottheta) prove that cot(A+B)=(cotAcotB-1)/(cotA+cotB)

Prove that : cot (A-B)= (cotA cot B+1)/(cotB -cotA) .

Prove that : cot (A+B)= (cotA cot B-1)/(cotB + cotA) .

If ((cotAcotB-1))/((cotB+cotA))=x then the value of x is

If A+B=225^(@) then (cotA)/(1+cotA).(cotB)/(1+cotB) = ………….

If A+B =225^(@) then the value of (cotA)/(1+cotA).(cotB)/(1+cotB) is

If A+B=225^(@) than prove that (cot A)/(1+cotA). (cot B)/(1+cotB)=(1)/(2)

If A+B=225^(@) , then find the value of (cotA)/(1+cotA)xx(cot B)/(1+cotB)

If A+B=225^(@) , then find the value of (cotA)/(1+cotA)xx(cot B)/(1+cotB)