If in 100 mL of an aqueous HCI of pH 10, 900 mL of distilled water is added, the pH of the resultant solution will be

In 100 mL of an aqueous HCl of pH 1.0, 900 mL of distilled water is added, the pH of the resultant becomes:

75 mL of 0.2 M HCl is mixed with 25 mL of 1 M HCl. To this solution, 300 mL of distilled water is added. What is the pH of the resultant solution?

75 mL of 0.2 M HCl is mixed with 25 mL of 1 M HCl . To this solution 300 mL of distilled water is added. What is the pH of the resultant solution ?

If HCl is added to distilled water, the pH of new solution will be:

100 cc of HCl of pH value 1 is mixed with 100 cc of distilled water. The pH value of the resultant solution is

The pH of solution is 5.0 to a 10 mL of solution 990 mL of water is add then pH of the resulting solution is

The pH of a solution is 5.0 . To a 10 ml of this solution , 990 ml of water is added . Then the pH of the resulting solution is

At 90^(@) C, pure water has [H^(+)]=10^(-6) M.If 100 mL of 0.2 M HCl is added to 200 mL of 0.1 M KOH at 90^(@) C then pH of the resulting solution will be :

At 90^(@) C, pure water has [H^(+)]=10^(-6) M.If 100 mL of 0.2 M HCl is added to 200 mL of 0.1 M KOH at 90^(@) C then pH of the resulting solution will be :