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`(3+5 omega+3 omega^(2))^(6)=64`.

(3 + 5 omega + 3omega^(2))^(6) =

(3+5omega+3omega^(2))^(6)

If 1, omega, omega^(2) are three cube roots of unity, prove that (3+ 5omega + 3omega^(2))^(6) = (3 + 5omega^(2) + 3omega)^(6)= 64

If 1, omega, omega^(2) are three cube roots of unity, prove that (1- omega- omega^(2))^(6)= 64

(2 + 5 omega + 2 omega ^ (2)) ^ (6) = (2 + 2 omega + 5 omega ^ (2)) ^ (6) = 729

(2 + omega + omega ^ (2)) ^ (3) + (1 + omega-omega ^ (2)) ^ (3) = (1-3 omega + omega ^ (2)) ^ (4) = 1

If omega,omega^(2) be imaginary cube root of unity then (3+3 omega+5 omega^(2))^(6)-(2+6 omega+2 omega^(2))^(3) is equal to

If omega is complex cube root of unity then (3+5 omega+3 omega^(2))^(2)+(3+3 omega+5 omega^(2))^(2) is equal to

If omega is complex cube root of unity then (3+5 omega+3 omega^(2))^(2)+(3+3 omega+5 omega^(2))^(2) is equal to

If omega is a complex cube root of unity, then show that: (1 + omega - omega^2)^6 = 64