Home
Class 12
CHEMISTRY
0.27 g of a long chain fatty acid was di...

0.27 g of a long chain fatty acid was dissolved in ` 100 cm^ 3 ` of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. The height of the monolayer is ` 10 ^( -x ) ` m. what is numerical value of `x ` ? [Density of fatty acid ` = 0.9 g cm ^ ( -3) , pi = 3 ` ]

Promotional Banner

Similar Questions

Explore conceptually related problems

0.27 g of a long chain fatty acid was dissolved in 100cm^(3) of hexane. 10ml of this solution was added dropwise to the surface of water in a round watch glass . Hexane evaporates and a monolayeer is formed. The distance from edge to center of the watch glass is 10 cm . What is the height of the monolayers? ["Density of fatty acid "=0.9 g cm^(-3),pi=3]

A watch-maker's glass is a

0.27 g of fatty acid is dissolved in 100 ml of solvent, 10 ml such solution is taken & placed over round plate. Distance from the centre of edge of round plate is 10 cm. Now solvent is evaporated & only fatty acid is remained. Density of fatty acid is 0.9g//c . Determine height of fatty acid layer. (pi=3)

0.27 g of fatty acid is dissolved in 100 ml of solvent, 10 ml such solution is taken & placed over round plate. Distance from the centre of edge of round plate is 10 cm. Now solvent is evaporated & only fatty acid is remained. Density of fatty acid is 0.9g//c . Determine height of fatty acid layer. (pi=3)

2.52 g of oxalic acid dehydrate was dissolved in 100 ml of water, 10 mL of this solution was diluted to 500 mL. The normality of the final solution and the amount of oxalic acid (mg/mL) in the solution are respectively-

Long chain molecules of fatty acids are formed by

Long chain molecules of fatty acids are formed by

From a point source a light falls on a spherical glass surface ( mu = 1.5 and radius of curvature = 10 cm ). The distance between point source and glass surface is 50 cm . The position of image is

From a point source a light falls on a spherical glass surface ( mu = 1.5 and radius of curvature = 10 cm ). The distance between point source and glass surface is 50 cm . The position of image is