Find the abscissa of the point on the curve `x^(3)=ay^(2)`, the normal at which cuts off equal intecepts from the coordinate axes.

The abscissa of the point on the curve ay^(2)=x^(3), the normal at which cuts off equal intercepts from the coordinate axes is

The abscissa of the point on the curve ay^(2)=x^(3) , the normal at which cuts off equal intercepts from the coordinate axes is

The abscissa of the point on the curve ay^2 = x^3 , the normal at which cuts off equal intercepts from the coordinate axes is

The abscissa of the point on the curve ay^2 = x^3 , the normal at which cuts off equal intercepts from the coordinate axes is

Find the abscissa of the point on the curve xy=(c+x)^(2) , the normal at which cuts off numerically equal intercepts from the axes of coordinates.

The abscissa of a point on the curve xy=(a+x)^(2), the normal which cuts off numerically equal intercepts from the coordinate axes,is -(1)/(sqrt(2)) (b) sqrt(2)a( c) (a)/(sqrt(2))(d)-sqrt(2)a

The abscissa of a point on the curve x y=(a+x)^2, the normal which cuts off numerically equal intercepts from the coordinate axes, is -1/(sqrt(2)) (b) sqrt(2)a (c) a/(sqrt(2)) (d) -sqrt(2)a

The abscissa of a point on the curve x y=(a+x)^2, the normal which cuts off numerically equal intercepts from the coordinate axes, is (a) -1/(sqrt(2)) (b) sqrt(2)a (c) a/(sqrt(2)) (d) -sqrt(2)a

The abscissa of a point on the curve x y=(a+x)^2, the normal which cuts off numerically equal intercepts from the coordinate axes, is -1/(sqrt(2)) (b) sqrt(2)a (c) a/(sqrt(2)) (d) -sqrt(2)a