z^(2)+19z-150

If x^(2) + 3y^(2) + 4z^(2)+ 19 = 4 sqrt(3) ( x + y + z) , then the value of ( x - y + 4z) is:

Obtain all other zeroes of 2z^4+z^3-14z^2-19z-6 if two of its zeroes are -1 and -2 .

Let (x,y,z) be an arbitrary point lying on a plane P which passes through the points (42,0,0), (0,42,0) and (0,0,42), then the value of the expression 3+(x-11)/((y-19)^(2)(z-12)^(2))+(y-19)/((x-11)^(2)(z-12)^(2))+(z-12)/((x-11)^(2)(y-19)^(2))-(x+y+z)/(14(x-11)(y-19)(z-12)) is equal to :

The radius of the circle in which the sphere x^(2)=y^(2)+z^(2)+2z-2y-4z-19=0 is cut by the plane x+2y+2z+7=0 is

If z_(1) and z_(2) are two complex numbers,then (A) 2(|z|^(2)+|z_(2)|^(2)) = |z_(1)+z_(2)|^(2)+|z_(1)-z_(2)|^(2) (B) |z_(1)+sqrt(z_(1)^(2)-z_(2)^(2))|+|z_(1)-sqrt(z_(1)^(2)-z_(2)^(2))| = |z_(1)+z_(2)|+|z_(1)-z_(2)| (C) |(z_(1)+z_(2))/(2)+sqrt(z_(1)z_(2))|+|(z_(1)+z_(2))/(2)-sqrt(z_(1)z_(2))|=|z_(1)|+|z_(2)| (D) |z_(1)+z_(2)|^(2)-|z_(1)-z_(2)|^(2) = 2(z_(1)bar(z)_(2)+bar(z)_(1)z_(2))

The equation of the plane containing the line 2x-y+z-3=0 , 3x+y+z=5 and at a distance of (1)/(sqrt(6)) from the point (2,1,-1) is 62x+29y+19z-k=0. Then the sum of digits of K is

x,y,z be a point on plane passing through (42,0,0),(0,42,0),(0,0,42) then value of (x-11)/((y-19)^2* (z-12)^2 )+(y-19)/((x-11)^2* (z-12)^2) +(z-12)/((x-11)^2* (y-19)^2)+3 -(x+y+z)/(14(x-11)* (z-12)*(y-19) )

If x + y + z = 19, x^2 +y^2+z^2=133 and xz=y^2, x>z>0 , what is the value of (x-z) ? यदि x + y + z = 19, x^2 +y^2+z^2=133 और xz=y^2, x>z>0 तो (x-z) का मान ज्ञात करें: