In a certain obervation we got,`l = 23.2cm,r =1.32cm` and time taken for 10 oscillations was 10.0 s. Find, maximum percentage error in determinaton of 'g'.

In a certain observation we get l =23.2 cm,r=1.32cm and time taken for 20 oscillations was 20.0 sec. Taking pi^2=10, find the value of g in proper significant figures.

In a certain observation we get l =23.2 cm,r=1.32cm and time taken for 20 oscillations was 20.0 sec. Taking pi^2=10, find the value of g in proper significant figures.

A wire of length l =6 +- 0.06cm and radius r =0.5+-0.005 cm and mass m =0. 3+-0.003gm . Maximum percentage error in density is

The acceleration due to gravity is determined by using a simple pendulum of length l = (100 pm 0.1)cm . If its time period is T = (2 pm 0.01)s , find the maximum percentage error in the measurement of g.

The period of oscillation of a simple pendulum is given by T=2pi sqrt((l)/(g)) . The length l of the pendulum is about 0.5s. The time of 100 oscillations is measured with a watch of 1 s resolution. Calcualte percentage error in measurment of g.

A wire of length l = 6+- 0.06 cm and radius r = 0.5 +- 0.005 cm and mass m = 0.3 +- 0.003 g . Maximum percentage error in density is :

Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period .

Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period .